in an attempt to to provide a means of generation of NO cheaply, gaseous NH3 is burned with 20% excess oxygen according to the equation
4NH3+5O2=4NO+6H2O
The reaction is 70% complete. the NO is separated from the unreacted NH3, and thelatter is recycled. compute 1. moles ofNO formed per 100 moles of NH3 feed and the moles of NH3 recycled per mole of NO formed
For every 100 mol NH3 used 100 mols NO formed at 100% yield. At 70% yield it will form only 70 mols NO.
Then 100 molos NH3 initially - 70 mols used = 30 moles left over to be recycled.
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To solve this problem, we need to follow the given information and use stoichiometry to determine the moles of NO formed per 100 moles of NH3 feed, as well as the moles of NH3 recycled per mole of NO formed.
1. Moles of NO formed per 100 moles of NH3 feed:
a) Starting with 100 moles of NH3 feed:
From the balanced equation, we can see that 4 moles of NH3 react to form 4 moles of NO.
Therefore, for every 100 moles of NH3 fed, we will get (4/4) * 100 = 100 moles of NO.
b) Considering that the reaction is only 70% complete:
For every 100 moles of NH3 fed, only 70% will react to form NO.
Therefore, the actual moles of NO formed per 100 moles of NH3 feed would be 70% of 100 moles, which is (70/100) * 100 = 70 moles of NO.
2. Moles of NH3 recycled per mole of NO formed:
a) From the balanced equation, we know that 4 moles of NH3 react to form 4 moles of NO.
Therefore, the molar ratio of NH3 to NO is 4:4, which simplifies to 1:1.
b) Since the ratio is 1:1, we don't need to consider the reaction completion percentage.
For every mole of NO formed, we will recycle 1 mole of NH3.
In summary:
1. Moles of NO formed per 100 moles of NH3 feed: 70 moles of NO
2. Moles of NH3 recycled per mole of NO formed: 1 mole of NH3
To find the moles of NO formed per 100 moles of NH3 feed, we need to calculate the moles of NO formed and the moles of NH3 feed.
First, let's calculate the moles of NO formed. We know that the reaction is 70% complete, so 70% of the NH3 has reacted to form NO.
Since the balanced chemical equation shows that 4 moles of NH3 react to produce 4 moles of NO, we can write a proportion to find the moles of NO formed:
(70 moles NH3 / 100 moles NH3) * 4 moles NO = 2.8 moles NO
Therefore, 2.8 moles of NO are formed per 100 moles of NH3 feed.
To calculate the moles of NH3 recycled per mole of NO formed, we need to consider that only 70% of the NH3 is consumed in the reaction. Therefore, 30% of the NH3 is recycled.
Since the balanced chemical equation shows that 4 moles of NH3 react to produce 4 moles of NO, we can write a proportion to find the moles of NH3 recycled:
(30 moles NH3 / 100 moles NH3) * 4 moles NH3 = 1.2 moles NH3
Therefore, 1.2 moles of NH3 are recycled per mole of NO formed.
In summary:
- Moles of NO formed per 100 moles of NH3 feed: 2.8 moles NO/100 moles NH3
- Moles of NH3 recycled per mole of NO formed: 1.2 moles NH3/1 mole NO