mark went to the department store to buy gifts for his friends. he spent half of his money plus 50 at store A. he then spent half of the remaining money plus 100 at store b at the end he had 250. how much money did he have at the beginning

money at beginning --- x

money spent in store A = x/2 + 50
amount left after shopping in A = x - x/2 - 50
= x/2 - 50

money spent in store B = (1/2)(x/2 - 50)+100
= x/4 - 25 + 100
= x/4 + 75

amount left = x/2 - 50 - (x/4 + 75)
= x/4 - 125
but that is 250

x/4 - 125 = 250
x/4 = 375
x = 1500
He started with 1500 units of money

check:
amount spent in store A = 800
amount left after that = 700
amount spent in store B = 450
amount left = 700 - 450
= 250 , yeahhh

To find out how much money Mark had at the beginning, we can work backwards with the information given.

Let's assume Mark had x amount of money at the beginning.

According to the information given, he spent half of his money plus 50 at store A. This means he spent (0.5x + 50) at store A.

After this, he had half of the remaining money plus 100. This means he had (0.5x - (0.5x + 50) + 100) left.

Finally, he had 250 units of money remaining. So we can set up the following equation:

(0.5x - (0.5x + 50) + 100) = 250

Simplifying the equation:

0.5x - 0.5x - 50 + 100 = 250

-50 + 100 = 250

50 = 250

This equation is not true, which means there is no solution to the equation. Therefore, there is no initial amount of money that satisfies all the given conditions.

Please double-check the information provided to see if there might be any mistakes or missing details.