I am a four digit number my ones digit is four less than my hundreds digit which is three times my tens digit which is half my thousands digit which can be divided by 1 2 or 3 with out a remainder what is my number

Let's break down the information given:

1. The ones digit is four less than the hundreds digit.
2. The hundreds digit is three times the tens digit.
3. The tens digit is half the thousands digit.
4. The thousands digit is divisible by 1, 2, and 3 without a remainder.

Let's start with the fourth piece of information:
- The thousands digit is divisible by 1, 2, and 3 without a remainder.
- The only digit that satisfies this condition is 6 (the only common divisor of 1, 2, and 3).
- Therefore, the thousands digit is 6.

Now let's move on to the third piece of information:
- The tens digit is half the thousands digit.
- Since the thousands digit is 6, the tens digit is half of 6, which is 3.

Next, let's consider the second piece of information:
- The hundreds digit is three times the tens digit.
- Since the tens digit is 3, the hundreds digit is three times 3, which is 9.

Finally, let's look at the first piece of information:
- The ones digit is four less than the hundreds digit.
- Since the hundreds digit is 9, the ones digit is 9 - 4, which is 5.

Putting it all together, the four-digit number that satisfies all the given conditions is 9365.

To find the four-digit number that satisfies the given conditions, we'll break down the clues step by step:

1. The ones digit is four less than the hundreds digit.
Let's represent the ones digit as x and the hundreds digit as y. According to the clue, x = y - 4.

2. The hundreds digit is three times the tens digit.
The tens digit can be represented as z. Based on the clue, y = 3z.

3. The tens digit is half the thousands digit.
The thousands digit can be represented as w. With this clue, z = w/2.

4. The thousands digit is divisible by 1, 2, and 3 with no remainder.
This tells us that w is a multiple of 2 and 3, so it must be a multiple of 6.

Let's find all possible values for w (the thousands digit) that satisfy the condition:

Multiples of 6: 6, 12, 18, 24, 30, 36, ...

Now, let's calculate the corresponding values for z (the tens digit), y (the hundreds digit), and x (the ones digit) based on the previous clues using the derived equations.

For w = 6:
z = 6 / 2 = 3
y = 3 * 3 = 9
x = 9 - 4 = 5
Thus, the four-digit number is 6539.

For w = 12:
z = 12 / 2 = 6
y = 3 * 6 = 18
x = 18 - 4 = 14 (But since x should be a single digit, this does not satisfy the conditions.)

We can continue this process for the other multiples of 6, but as you can see, the only valid four-digit number that satisfies all the given conditions is 6539.