how many liters (at STP) of chlorine gas are required to produce .050L of hydrogen chloride gas?
H2 + Cl2 ==> 2HCl
Since these are gases one may use L (volume) as if the volume were mols.
0.5 L HCl x (1 mol H2/2 mols HCl) = 0.5 x 1/2 = ?
To determine the number of liters of chlorine gas required to produce 0.050 liters of hydrogen chloride gas, we need to understand the stoichiometry of the reaction between chlorine gas (Cl2) and hydrogen gas (H2) to produce hydrogen chloride gas (HCl).
The balanced chemical equation for the reaction is:
Cl2 + H2 -> 2HCl
From the equation, we can see that one molecule of chlorine gas reacts with one molecule of hydrogen gas to produce two molecules of hydrogen chloride gas. Therefore, the stoichiometric ratio of chlorine gas to hydrogen chloride gas is 1:2.
To find the volume of chlorine gas, we multiply the volume of hydrogen chloride gas by the stoichiometric ratio:
Volume of chlorine gas = Volume of hydrogen chloride gas * (1/2)
Substituting the given value of 0.050 liters for the volume of hydrogen chloride gas:
Volume of chlorine gas = 0.050 liters * (1/2)
Volume of chlorine gas = 0.025 liters
Therefore, 0.025 liters (at STP) of chlorine gas are required to produce 0.050 liters of hydrogen chloride gas.