A metal x forms two different chloride.if 12.g of chloride A and 16.3g of chloride B contain 7.1g and 10.7g of chlorine respectively,show that the figure agree with the laws of multiple proportions.write there formulea

plz i need the work....no hint plz

To determine if the given figures agree with the laws of multiple proportions, we will compare the ratio of chlorine in chloride A to chloride B with the ratio of their respective weights.

Let's assume the metal X has the symbol "M."

From the given information, we have the following:

Mass of chloride A (m1) = 12.0 g
Mass of chloride B (m2) = 16.3 g
Mass of chlorine in chloride A (m1c) = 7.1 g
Mass of chlorine in chloride B (m2c) = 10.7 g

Now we can calculate the ratios:

Ratio of chlorine in chloride A to chloride B:
(m1c / m2c) = (7.1 g / 10.7 g)

Ratio of their respective weights:
(m1 / m2) = (12.0 g / 16.3 g)

Let's simplify these ratios:

(m1c / m2c) = (7.1 g / 10.7 g) = 0.664 (rounded to three decimal places)
(m1 / m2) = (12.0 g / 16.3 g) = 0.737 (rounded to three decimal places)

Now let's check if these ratios are approximately equal:

0.664 ≈ 0.737

Since the ratios are not equal, the given figures do not conform exactly to the laws of multiple proportions. However, they are relatively close, which suggests they are likely to be in accordance with the laws.

Now, let's write the formulas for chloride A and chloride B based on the given information:

The formula for chloride A (MClₓA):
Since the mass of chlorine in chloride A is 7.1 g, and the molar mass of chlorine is 35.45 g/mol, we can calculate the moles of chlorine as follows:
moles of chlorine in chloride A = (mass of chlorine / molar mass of chlorine)
moles of chlorine in chloride A = (7.1 g / 35.45 g/mol) = 0.2 mol

To find the formula, we compare the molar ratio of metal X to chlorine:
(moles of metal X / moles of chlorine) = (1 / 0.2) = 5
Therefore, the formula for chloride A is MCl₅.

The formula for chloride B (MClᵧB):
Using the same process, we find the moles of chlorine in chloride B:
moles of chlorine in chloride B = (10.7 g / 35.45 g/mol) = 0.302 mol

Comparing the molar ratio of metal X to chlorine:
(moles of metal X / moles of chlorine) = (1 / 0.302) ≈ 3.31
Therefore, the formula for chloride B is MCl₃.₃₁ (rounded to two decimal places).

Hence, the formulas for chloride A and chloride B are MCl₅ and MCl₃.₃₁, respectively.

To determine if the given figures agree with the laws of multiple proportions, we need to compare the ratios of the masses of chlorine in the two compounds with the ratios of the masses of the metal.

Let's start by finding the masses of the metal in chloride A and chloride B.

Given:
Mass of chloride A = 12.0g
Mass of chloride B = 16.3g

To find the mass of the metal in chloride A, we subtract the mass of chlorine from the mass of the compound:
Mass of metal in chloride A = Mass of chloride A - Mass of chlorine in chloride A
Mass of metal in chloride A = 12.0g - 7.1g
Mass of metal in chloride A = 4.9g

Similarly, to find the mass of the metal in chloride B:
Mass of metal in chloride B = Mass of chloride B - Mass of chlorine in chloride B
Mass of metal in chloride B = 16.3g - 10.7g
Mass of metal in chloride B = 5.6g

Now, let's calculate the ratio of the masses of the metal in chloride A and chloride B:
Metal ratio = Mass of metal in chloride A / Mass of metal in chloride B
Metal ratio = 4.9g / 5.6g
Metal ratio ≈ 0.875

Next, we need to calculate the ratio of the masses of chlorine in chloride A and chloride B:
Chlorine ratio = Mass of chlorine in chloride A / Mass of chlorine in chloride B
Chlorine ratio = 7.1g / 10.7g
Chlorine ratio ≈ 0.663

According to the law of multiple proportions, the ratio of the masses of the metal in two compounds should be consistent with the ratio of the masses of the different elements in those compounds.

Comparing the metal ratio (0.875) and chlorine ratio (0.663), we can see that these values are not equal. Therefore, the given figures do not agree with the laws of multiple proportions.

Additionally, we can find the formulas of the compounds based on these ratios. If we assume that chloride A (with the metal-to-chlorine ratio of 0.875) is a simpler compound, its formula could be XCl, where X represents the metal. Similarly, if we assume that chloride B (with the metal-to-chlorine ratio of 0.663) is a more complex compound, its formula could be XCl2.

To summarize:
Compound A: XCl
Compound B: XCl2