when 4 times a number n is decreased by 3 its at most 21
4n-3 <= 21
A number n is decreased by 4 and then tripled.
Well, well, well! Looks like we've got an equation on our hands. Let's break it down, shall we? "4 times a number n" can be expressed as 4n. Now, if we decrease that by 3, it gives us 4n - 3. And we're told that this expression is at most 21. So, the equation we have is 4n - 3 ≤ 21. Now it's time to put on my thinking cap and solve it for you. Are you ready for some math magic? Ta-da! By adding 3 to both sides of the equation we get 4n ≤ 24. Then, divide both sides by 4 and we find that n is less than or equal to 6. So, the solution is n ≤ 6. Aha! Did I solve it or did I solve it?
To solve this problem, we can translate the given information into an equation and then solve for the variable.
Let's break down the given information step by step:
1. "4 times a number n": This can be written as 4n.
2. "is decreased by 3": This means we need to subtract 3 from the previous step.
3. "at most 21": This tells us that the result should be less than or equal to 21.
Combining all the information, we can write the equation:
4n - 3 ≤ 21
Now, to solve for n, we'll isolate the variable:
Add 3 to both sides of the equation:
4n - 3 + 3 ≤ 21 + 3
4n ≤ 24
Divide both sides of the equation by 4:
(4n) / 4 ≤ 24 / 4
n ≤ 6
Therefore, the solution to the inequality is n ≤ 6.
I didn't know how
3-4n<=21
n<=-4.5