The graph represents function 1 and the equation represents function 2:

A graph with numbers 0 to 4 on the x-axis and y-axis at increments of 1. A horizontal straight line is drawn joining the ordered pairs 0, 3 and 4, 3.

Function 2
y = 3x + 1

How much more is the rate of change of function 2 than the rate of change of function 1?

1

2

3

4
I believe the answer is C.

I love school! oops typo I love not doing school!

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To find the rate of change of a function, we need to determine the slope of the graph or the coefficient of the corresponding variable in the equation.

For function 1, we have a straight horizontal line joining the ordered pairs (0, 3) and (4, 3). Since the y-values remain constant at 3, the slope is 0. The rate of change of function 1 is 0.

For function 2, the equation is y = 3x + 1. The coefficient of x, which is 3, represents the rate of change. Therefore, the rate of change of function 2 is 3.

To find the difference between the rate of change of function 2 and function 1, we subtract the rate of change of function 1 from the rate of change of function 2: 3 - 0 = 3.

Therefore, the correct answer is option C, 3. The rate of change of function 2 is 3 units higher than the rate of change of function 1.

yesssssssss

function 1 is y = 3 and slope = 0

function 2 has slope = 3

3/0 is UNDEFINED

So am I correct ?