For the following system of equations, what is the x-value of the solution?
-x+2y=6
6y=x+18
a. -18
b. 0
c. -6***
d. 3
-3 x + 6 y = 18
- x + 6 y = 18
-------------------subtract
-2 x = 0
x = 0
y = 3
So I get x = 0
so is the answer 0?
yes the answer is 0 ,
send the x to left side in the second equation and subtract both equation you get y =3
now put it in any of the equation you get the x value '0'.
To find the x-value of the solution to the given system of equations, we can use the method of substitution or elimination.
Let's solve the system of equations using the substitution method:
1. Solve one equation for x in terms of y.
From the second equation, we can rearrange it to isolate x:
x = 6y - 18
2. Substitute this expression for x into the other equation.
Now that we have an expression for x in terms of y, we substitute it into the first equation:
-(6y - 18) + 2y = 6
Simplify:
-6y + 18 + 2y = 6
Combine like terms:
-4y + 18 = 6
Subtract 18 from both sides:
-4y = -12
Divide both sides by -4:
y = 3
3. Substitute the value of y back into one of the original equations to find the x-value.
Let's substitute y = 3 into the second equation:
6(3) = x + 18
18 = x + 18
Subtract 18 from both sides:
0 = x
Therefore, the solution to the system of equations is x = 0.
So, the correct answer is b. 0.