The perimeter of Sophias garden is 42 meters. the garden is 6 meters wide. What is the length of the garden?
If the length is L, then
2(w+L) = 42
2(6+L) = 42
...
42/6 is indeed 7, but it is not the answer to the question.
the primeter of sofia garden is 42 m the garden is 6m wide .What is the length of the garden
Sofia
To find the length of Sophia's garden, we can use the formula for the perimeter of a rectangle. The perimeter of a rectangle is given by the equation P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
In this case, we are given that the perimeter is 42 meters and the width is 6 meters. So we can plug in these values into the formula and solve for the length:
42 = 2(l + 6)
First, we can simplify the equation by dividing both sides by 2:
21 = l + 6
Next, we can isolate the variable l by subtracting 6 from both sides:
21 - 6 = l
15 = l
Therefore, the length of Sophia's garden is 15 meters.