A man is 4times old as his son.After 16years he will be only twice as old as his son.Find their present age.
The son is 8 years old.
4x+16 = 2x+32
-16 -16
4x = 2x+16
-2x -2x
2x = 16
*1/2 *1/2
x = 8
(4*8)+16 = 48
Father is 48 years old.
4*x=4+3*x
4x=4+3x
4x-3x=4
x=4
Son's present age --- x
Man's present age --- 4x
16 years from now:
son --> x+16
man --> 4x+16
solve ....
4x+16 = 2(x+16)
To find the present ages of the man and his son, let's assign variables to their ages. Let's say the son's age is "x" and the man's age is "4x".
According to the given information, after 16 years (in the future), the man's age will be twice that of his son's age. So, we can create an equation based on this information:
4x + 16 = 2(x + 16)
Let's solve this equation to find the value of "x", which represents the son's present age:
4x + 16 = 2x + 32
2x = 16
x = 8
Now that we know the son's present age is 8, we can easily find the man's present age by substituting this value into one of the variables we assigned earlier.
So, the man's present age is 4x = 4 * 8 = 32.
Therefore, the son's present age is 8 and the man's present age is 32.