calculate the concentration of potassium in grams per liter after mixing 100ml of 0.250m and 200ml of 1.00m k2s04
final concentration (equal volumes) will be (.250+1.0)/2= .625M
grams per liter: .625*39*2 grams/liter
You need to learn where the caps key is and use it. m stands for molality; M stands for molarity. Which do you mean?
To calculate the concentration of potassium (K) in grams per liter (g/L) after mixing two solutions, you need to consider the molar concentration (M) and the molar mass of potassium (K).
Here's how you can calculate it step by step:
Step 1: Calculate the moles of potassium in each solution.
To do this, you need to know the molar concentration (M) and the volume (V) of each solution.
For the first solution:
Molar concentration (M1) = 0.250 M
Volume (V1) = 100 mL = 0.100 L
To find the moles in the first solution:
moles of K1 = M1 × V1
For the second solution:
M2 = 1.00 M
V2 = 200 mL = 0.200 L
moles of K2 = M2 × V2
Step 2: Calculate the total moles of potassium.
To find the total moles of potassium after mixing the two solutions, you need to add the moles from each solution.
total moles of K = moles of K1 + moles of K2
Step 3: Calculate the concentration of potassium in grams per liter.
To do this, you need to know the molar mass of potassium (K), which is approximately 39.1 g/mol.
molar mass of K = 39.1 g/mol
To find the concentration of potassium (g/L):
concentration of K = (total moles of K × molar mass of K) / total volume of the solution
Since the total volume is equal to the sum of the volumes of the two solutions, which is 100 mL + 200 mL = 300 mL = 0.300 L, we can substitute these values into the equation.
concentration of K = (total moles of K × molar mass of K) / 0.300 L
Now you can substitute the values you obtained in step 1 and step 2 into the equation to find the concentration of potassium in grams per liter.