How do you Find the lateral area of a square pyramid. base:8

Height:22. and side:8 Help pls

Okay can everyone keep drama aside pick a random name and help people with homework please

I am the real Sue here not you OK and i never talk like that fake Mrs. sue and i know who you are OK you will be kicked out of jiskha OK.

did I not do this right below here?

http://www.jiskha.com/display.cgi?id=1452283876#1452283876.1452284419

Not okay.

To find the lateral area of a square pyramid, you'll need to follow these steps:

1. Determine the slant height of the pyramid using the Pythagorean theorem. In this case, the base of the pyramid is a square with a side length of 8, and the height is 22. The slant height can be found by applying the Pythagorean theorem, which states that the square of the hypotenuse (slant height) is equal to the sum of the squares of the other two sides. So, since the base and height form a right triangle, we can calculate the slant height as follows:
Slant height = sqrt(8^2 + 22^2)

2. Calculate the perimeter of the base, which is a square. Since the side length of the square is given as 8, the perimeter can be found by multiplying the side length (8) by 4:
Perimeter of the base = 4 * 8

3. Finally, calculate the lateral area by multiplying the perimeter of the base by half the slant height:
Lateral area = (Perimeter of the base) * (Slant height / 2)

Putting it all together:
Slant height = sqrt(8^2 + 22^2)
Perimeter of the base = 4 * 8
Lateral area = (Perimeter of the base) * (Slant height / 2)

Once you have the values for the slant height and perimeter of the base, substitute them into the formula to calculate the lateral area of the square pyramid.

mrs. sue

You spelled Ms. Sue's name wrong doofus also Ms. Sue would never talk like that please dont pretend to be someone you're not