A sells an article to B at a profit of 20%, B sells the same to C at a profit of 10%. If C pay Rs 6600. what did it cost to A?
A * 1.2 = B
A * 1.2 * 1.1 = C = 6600
so
A = 6600/(1.2*1.1)
How u take 1.2 and 1.1?
multiply
1.2 * 1.1 = 1.32
so the price increased a total of 32 percent.
6600/1.32 = ?
To find the cost price of the article for A, we need to work backwards.
Let's assume the cost price of the article for A is x.
A sells the article to B at a profit of 20%. Profit is calculated as a percentage of the cost price. Therefore, A sells the article to B at a price of x + 20% of x.
Price at which A sells to B = x + (20/100) * x = 1.2x.
Now, B sells the same article to C at a profit of 10%. B sells the article to C at a price of 1.2x + 10% of (1.2x).
Price at which B sells to C = 1.2x + (10/100) * (1.2x) = 1.2x + 0.12x = 1.32x.
Given that C pays Rs 6600 for the article, we can set up the equation:
1.32x = 6600.
Now, we can solve for x:
x = 6600 / 1.32 = Rs 5000.
Therefore, the cost of the article for A is Rs 5000.