The length of rectangle is twice its width,and its perimetet is 90. What is its area?
P = 2L + 2W
90 = 2(2W) * 2W
90 = 6W
15 = W
30 = L
A = LW
The less of a rectangle is one third the width write an expression for the area and perimeter
To find the area of a rectangle, we need to know the length and width. In this case, let's assume that the width of the rectangle is 'w'.
According to the problem, the length of the rectangle is twice its width. So, the length would be '2w'.
The formula for calculating the perimeter of a rectangle is given by:
Perimeter = 2 × (Length + Width)
Given that the perimeter is 90, we can substitute the values and solve for 'w':
90 = 2 × (2w + w)
Simplifying the equation:
90 = 2 × 3w
45 = 3w
w = 15
Now that we have the width of the rectangle (w = 15), we can find the length by substituting it back into the expression for the length:
Length = 2w = 2 × 15 = 30
To calculate the area of a rectangle, we use the formula:
Area = Length × Width
Substituting the values:
Area = 30 × 15 = 450 square units
Therefore, the area of the rectangle is 450 square units.