13.5g aluminium changes to Al^3+ in solution by loosing ..... electrons.
Al is 27 g/mol
so we have
3 * (13.5/27) * 6 *10^23 electrons lost
To determine how many electrons the aluminum atom loses to become an Al³⁺ ion, we need to look at the electron configuration of aluminum.
Aluminum has an atomic number of 13, meaning it has 13 electrons. The electron configuration of aluminum is: 1s² 2s² 2p⁶ 3s² 3p¹.
To form an Al³⁺ ion, aluminum loses three electrons. We can see this by removing the three valence electrons from the 3p orbital, resulting in the configuration: 1s² 2s² 2p⁶.
Therefore, when aluminum changes to Al³⁺ in solution, it loses three electrons.
To determine the number of electrons lost by 13.5g of aluminum (Al) when it forms Al^3+ ions in a solution, we need to use the concepts of molar mass and the charge of the ion.
1. Find the molar mass of aluminum (Al):
The molar mass of aluminum is found on the periodic table. The atomic mass of aluminum is approximately 26.982 g/mol.
2. Determine the number of moles:
Using the molar mass, we can calculate the number of moles in 13.5g of aluminum by dividing the mass by the molar mass:
Number of moles = Mass / Molar mass
Number of moles = 13.5g / 26.982 g/mol
3. Calculate the number of moles of Al^3+ ions formed:
Since aluminum (Al) forms Al^3+ ions by losing electrons, each aluminum atom loses three electrons to become Al^3+. Hence, the number of moles of Al^3+ ions formed will be the same as the number of moles of aluminum used.
4. Determine the number of electrons lost:
One mole of electrons corresponds to Avogadro's number (6.022 x 10^23) of electrons. Therefore, the number of electrons lost can be calculated by multiplying the number of moles of Al^3+ ions formed by Avogadro's number:
Number of electrons lost = Number of moles of Al^3+ ions formed x Avogadro's number
Now, let's plug in the values and calculate the number of electrons lost:
Number of moles = 13.5g / 26.982 g/mol
Number of moles = 0.500 mol
Number of electrons lost = 0.500 mol x 6.022 x 10^23/mol
The final answer will be the calculated value of the number of electrons lost.