Two numbers are in the ratio of 7:9, the smaller is 42, what is the larger?
I the two numbers are in the ratio of 7:9 we can call the numbers 7x and 9x.
You are given that
7x = 42
carry on.
96
To find the larger number, you can set up a proportion using the given ratio and the value of the smaller number.
The ratio is given as 7:9, which means that the first number is seven times smaller than the second number.
Let's represent the larger number as "x".
Since the smaller number is 42, we can set up the proportion as follows:
42 / x = 7 / 9
To solve for "x", we can cross-multiply:
42 * 9 = 7 * x
Now, we can simplify and solve for "x":
378 = 7x
To isolate "x", we divide both sides of the equation by 7:
378 / 7 = x
The result is:
x = 54
Therefore, the larger number is 54.