when an electron is accelerated through a potential difference of 1 V, the kinetic energy at the end of the field is?
1 electron volt
or
1.6*10^-19 Joule
To calculate the kinetic energy of an electron after being accelerated through a potential difference of 1 volt, you can use the equation:
Kinetic Energy (KE) = qV
Where:
- KE is the kinetic energy of the electron
- q is the charge of the electron (1.6 x 10^(-19) coulombs)
- V is the potential difference (1 volt)
Now let's substitute the values into the equation:
KE = (1.6 x 10^(-19) C) x (1 V)
KE = 1.6 x 10^(-19) J
Therefore, the kinetic energy of the electron at the end of the field is 1.6 x 10^(-19) joules.