when an electron is accelerated through a potential difference of 1 V, the kinetic energy at the end of the field is?

1 electron volt

or
1.6*10^-19 Joule

To calculate the kinetic energy of an electron after being accelerated through a potential difference of 1 volt, you can use the equation:

Kinetic Energy (KE) = qV

Where:
- KE is the kinetic energy of the electron
- q is the charge of the electron (1.6 x 10^(-19) coulombs)
- V is the potential difference (1 volt)

Now let's substitute the values into the equation:

KE = (1.6 x 10^(-19) C) x (1 V)

KE = 1.6 x 10^(-19) J

Therefore, the kinetic energy of the electron at the end of the field is 1.6 x 10^(-19) joules.