Kim is 7 years older than May. If three times Kim's age plus 5 times May's age is equal to 165, what are the ages of Kim and May?
kim is 25
may is 18
btw im in year 5
To solve this problem, let's assign variables to the ages of Kim and May. Let's say Kim's age is 'k' and May's age is 'm'.
From the given information, we know that Kim is 7 years older than May. So, we can write the first equation as:
k = m + 7
The next piece of information is that three times Kim's age plus five times May's age is equal to 165. Mathematically, this can be written as:
3k + 5m = 165
Now we have a system of two equations. We can solve these equations simultaneously to find the values of 'k' and 'm'.
We can start by substituting the value of 'k' in terms of 'm' from the first equation into the second equation:
3(m + 7) + 5m = 165
Next, distribute the 3 to the terms in the parentheses:
3m + 21 + 5m = 165
Combine like terms:
8m + 21 = 165
Now, isolate the variable 'm' by subtracting 21 from both sides of the equation:
8m = 165 - 21
8m = 144
Finally, divide both sides of the equation by 8 to solve for 'm':
m = 144/8
m = 18
Now that we know the value of 'm', we can substitute it back into the first equation to find the value of 'k':
k = m + 7
k = 18 + 7
k = 25
Therefore, May's age is 18 and Kim's age is 25.
Kim is x+7years and May is x years old. So 3(x+7) + 5x = 165. 8x + 21 = 165. 8X= 144 X= 18. So Kim is 18+7 which is 25years and May is 18years
k = m +7
3(m+7) + 5 m = 165