report on the preparation of 0.004M stock solution of ethanoic acid
How much of the stock solution do you need to prepare?
Then mols you need = M x L = ?
Then mol = grams/molar mass. You know molar mass of the material and mols, solve for grams.
Then mols you need = M x L = ?
Then mol = grams/molar mass. You know molar mass of the material and mols, solve for grams.