two urn contain respectively 3 white, 7 red, 15 black and 10 white ,6 red and 9 black balls. one ball is drawn from each urn. what is the probabilit
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To find the probability, we need to determine the number of favorable outcomes and the number of total possible outcomes.
Let's consider each urn separately.
In the first urn, there are a total of 3 + 7 + 15 = 25 balls.
In the second urn, there are a total of 10 + 6 + 9 = 25 balls.
Now, let's calculate the number of favorable outcomes where we draw a white ball from the first urn and a red ball from the second urn.
The number of ways to choose a white ball from the first urn is 3, and the number of ways to choose a red ball from the second urn is 6. Therefore, the number of favorable outcomes is 3 * 6 = 18.
The total number of possible outcomes is the product of the number of balls in each urn, which is 25 * 25 = 625.
Therefore, the probability of drawing a white ball from the first urn and a red ball from the second urn is 18/625.