How many grams of SrCl2 is required to prepare 1 molar solution of it,
How much do you need to prepare?
mols needed = M x L = ?
Then mols = grams/molar mass. You know mols and molar mass, solve for grams.
grams of srcl2 over 1, hen this is the answer
To determine the number of grams of SrCl2 required to prepare a 1 molar solution, you need to know the molar mass of SrCl2.
The molar mass of SrCl2 can be calculated by adding up the atomic masses of its constituent elements, which are Strontium (Sr) and Chlorine (Cl).
The atomic mass of Sr is 87.62 g/mol, and the atomic mass of Cl is 35.45 g/mol.
So, to find the molar mass of SrCl2, you calculate:
Molar Mass of SrCl2 = (Atomic Mass of Sr) + 2 * (Atomic Mass of Cl)
= 87.62 g/mol + 2 * 35.45 g/mol
= 87.62 g/mol + 70.90 g/mol
= 158.52 g/mol
Now, to prepare a 1 molar solution of SrCl2, you need 1 mole of SrCl2 in 1 liter of solution (assuming the solution volume is 1 liter).
Since the molar mass of SrCl2 is 158.52 g/mol, you will need 158.52 grams of SrCl2 to prepare a 1 molar solution of it.
Please note that if the volume of your solution is not 1 liter, you will need to adjust the amount of SrCl2 accordingly.