Write the equation of a line that is perpendicular to the given line and passes through the given point.
y-3=8/3(x+20;(-2,3)
Just too weird. I bet you intended to type:
y-3=(8/3)(x+2);(-2,3)
That line passes through (-2,3) already, just the slope is wrong.
try:
y-3=(-3/8)(x+2);(-2,3)