Solve the equation for A.
12AB + 7B = 5A
Please help, I am completely stuck.
12AB + 7B = 5A.
12AB - 5A = -7B.
A(12B - 5) = -7B.
Divide by (12B-5):
A = -(7B/(12B-5)).
I thought you couldn't just switch 5A and 7B like that?
12AB + 7B = 5A. 7B = 5A - 12AB, 7B =A(5 - 12B). Divide both sides by (5 - 12B) 7B/(5 - 12B) = A
Can you cancel out the B in your final answer?
Like make your final answer 7/5-12? which would equal to -1?
Since there are 2 variables and only 1 Eq, I have to solve for 1 variable in terms of the other.
To solve the equation for A, we need to isolate the variable A on one side of the equation. Let's go step by step.
Start with the equation:
12AB + 7B = 5A
Step 1: Group the terms with A on one side and the terms without A on the other side. We do this by subtracting 5A from both sides of the equation:
12AB - 5A + 7B = 0
Step 2: Factor out the common factor A on the left side of the equation:
A(12B - 5) + 7B = 0
Step 3: Now, isolate A by dividing both sides of the equation by the coefficient of A, which is (12B - 5):
A = -7B / (12B - 5)
And that's the solution for A.