On the third day of Statistics, my teacher gave to me….three French hens. Because she is in a hurry, she randomly selects three pets from the local pet store. Find the probability that she selected three French hens.
Hens Chickens
French 10 20
American 30 40
In order to receive ANY credit, you must show correct formula, substitution and final answer
Let success be choosing a French hen out of all possible choices (Ω) and we need to assume the probability of choosing any pet is equal.
Probability of success (choosing a French hen)
=Number of French hens ÷ Total number of possible choices (&Omega).
Here you see that there are 10 French hens. Count the total number of possible choices to complete your answer.
So would it be 10 ÷ 40 ?
There are 10 French hens.
Try to enumerate the number of each kind of pet and then add up the numbers to get the total number of pets.
40 is the number of American chickens.
So it would 10÷ into 100 cause that the total possibility with hens and chickens all together ? Sorry im really bad at math
Yes, that would be correct, because
10+20+30+40=100
so the the probability that she selected French hens would be 10/100.
From the several back and forth replies, your post is not very clear.
looking at your chart, there are a total of 60 chicken, of which 10 are French hens
so prob(selecting 3 French hens from the 60 chicken)
= C(10,3)/C(60,3) = 120/34220
= 6/1711
you also make mention of selecting 3 pets.
I will assume that the only pets are the chickens
Since the name "chicken" to me means both female and male, there are only 60 chickens in total.
Good catch Reiny! I read too fast!
To "Help", please go along with Reiny's answer.