A student mixed 1.5g of CaO with 2.5M HNO3. How many moles of CaO were reacted
CaO + 2HNO3 ---> H2O + Ca(NO3)2 ??
CaO = 40 + 16 = 56 grams/mol
so we have 1.5/56 = .0268 mols of CaO
To calculate the number of moles of CaO that were reacted, we need to use the given information and the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between CaO and HNO3 is:
CaO + 2HNO3 → Ca(NO3)2 + H2O
From this equation, we can see that 1 mole of CaO reacts with 2 moles of HNO3.
The molar mass of CaO (calcium oxide) is:
Ca = 40.08 g/mol
O = 16.00 g/mol
So, the molar mass of CaO = 40.08 + 16.00 = 56.08 g/mol
Now, we can calculate the number of moles of CaO:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 1.5 g / 56.08 g/mol ≈ 0.027 moles
Therefore, approximately 0.027 moles of CaO were reacted.
To determine the number of moles of CaO that were reacted, you'll need to use the given amount of CaO and the concentration of the HNO3 solution.
Let's start by calculating the number of moles of HNO3. You can use the formula:
moles = concentration (M) × volume (L)
Since the concentration is given as 2.5M, we need to find the volume of the HNO3 solution that was used in the reaction. Unfortunately, the volume is not provided, so we will need additional information to calculate it.
Once you have the volume of the HNO3 solution used in the reaction, you can calculate the moles of HNO3 by using the formula above.
Now, let's focus on the reaction between CaO and HNO3. The balanced equation is:
CaO + 2HNO3 -> Ca(NO3)2 + H2O
According to the balanced equation, one mole of CaO reacts with 2 moles of HNO3. This means that the moles of HNO3 reacted in the reaction are also the same as the moles of CaO reacted.
Finally, you can determine the number of moles of CaO reacted by using the calculated moles of HNO3.
Keep in mind that without the volume of the HNO3 solution used in the reaction, it is not possible to give an exact answer to the question.