Solve. 1-x/(x^-23x+2)(x^2+4)

To solve the expression 1 - x / [(x^(-2))3x + 2][(x^2) + 4], we need to simplify the expression and then solve for x.

Let's start by simplifying the expression within the parenthesis [(x^(-2))3x + 2][(x^2) + 4].

First, let's simplify the first term (x^(-2))3x:
(x^(-2))3x is equivalent to (3x)/(x^2).

Next, let's simplify the second term (x^2) + 4.

Now, we can rewrite the expression as follows:
1 - x / [(3x)/(x^2) + 2][(x^2) + 4]

To make further progress, let's find a common denominator for the terms within the parenthesis. The common denominator in this case would be (x^2), so we need to multiply the first term by (x^2)/(x^2) to obtain the common denominator.

Rewriting the expression:
1 - x / [(3x)(x^2) / (x^2) + 2(x^2) / (x^2)][(x^2) + 4]

Simplifying:
1 - x / [(3x^3 + 2(x^2)) / (x^2)][(x^2) + 4]

Next, let's evaluate the expression within the parenthesis.

Simplifying further:
1 - x * (x^2) / (3x^3 + 2(x^2))(x^2 + 4)

To simplify this expression, let's multiply the terms:

1 - (x^3) / (3x^3 + 2x^4 + 4x^2 + 8x^2)

Combining like terms:
1 - (x^3) / (2x^4 + 12x^2 + 3x^3 + 8x^2)

We have simplified the expression, but we cannot further solve it since we have both x^4 and x^3 terms.