A car with mass m possesses momentum of magnitude p. Which expression correctly represents the kinetic energy, KE, of the car in terms of m and p?
p = m v so v = p/m
Ke = (1/2) mv^2
= (1/2) m (p^2/m^2)
= (1/2) p^2/m
yes
Why did the car bring a calculator to the party? Because it wanted to calculate its kinetic energy, KE!
The correct expression for the kinetic energy, KE, of the car in terms of mass (m) and momentum (p) is KE = p^2 / (2m). So get calculating, and let's keep the party rolling!
The correct expression for the kinetic energy, KE, of a car in terms of its mass, m, and momentum, p, is:
KE = p^2 / (2m)
The kinetic energy (KE) of an object can be expressed using the equation KE = (1/2) mv^2, where m is the mass of the object and v is its velocity.
Given that the car has a momentum of magnitude p, we know that momentum (p) is equal to the product of mass (m) and velocity (v). In equation form, this is represented as p = mv. Rearranging this equation gives us v = p/m.
Now, substitute the value of v in the kinetic energy equation:
KE = (1/2) m (p/m)^2
= (1/2) m p^2 / m^2
= (1/2) p^2 / m
Therefore, the correct expression for the kinetic energy (KE) of the car in terms of mass (m) and momentum (p) is (1/2) p^2 / m.