mike is skiing downhill at a 25 degree angle. if his weight is 350N assuming there is no friction what is his acceleration

what is the force acting downhill?

F = ma

Hey Steve, can you also help my question too? I am Very confused at even how to approach the question.

To find Mike's acceleration while skiing downhill at a 25-degree angle, we can use the component of his weight force that acts in the direction of motion.

Here's how you can calculate it:

1. Start by finding the component of Mike's weight force that acts in the downhill direction. This can be found using the formula:

F_downhill = Weight * sin(angle)

Weight refers to Mike's weight, which is given as 350N, and angle is 25 degrees.
Therefore, the downhill component of the weight force can be calculated as:

F_downhill = 350N * sin(25°)

2. Next, since there is no friction mentioned in the problem, we can assume that all the downhill component of the weight force is responsible for the acceleration. So the downhill component of the weight force is equal to the force accelerating Mike downhill, which we'll call F_net.

F_net = F_downhill

3. Now, we can use Newton's second law of motion to calculate the acceleration:

F_net = m * a

Where F_net is the net force, m is the mass, and a is the acceleration.

Since we're given the weight, we can use it to find the mass using the formula:

Weight = m * g

Rearranging the formula to solve for m, we get:

m = Weight / g

Where g is the acceleration due to gravity, approximately 9.8 m/s^2.

Now, substitute the expression for m into the equation F_net = m*a:

F_downhill = (Weight / g) * a

Since F_downhill = F_net, we can write:

(350N * sin(25°)) = (Weight / g) * a

Solve for a by rearranging the equation:

a = (350N * sin(25°)) / (Weight / g)

Calculate the value:

a = (350N * sin(25°)) / (350N / 9.8 m/s^2)

Finally, calculate the value of a to find the acceleration of Mike skiing downhill.