in a single throw fair die what is probability that an odd number or perfect square greater then one show up
just did this , look two posts below this
owk I seing but I am not adstanding
To find the probability of an event, you need to determine the number of favorable outcomes (successes) and divide it by the total number of possible outcomes (sample space).
In this case, we need to calculate the probability of rolling an odd number or a perfect square greater than one on a fair die.
Step 1: Determine the favorable outcomes.
On a fair die, there are 6 possible outcomes since it has 6 sides numbered 1 to 6. We want to find the number of successful outcomes, which means getting an odd number (1, 3, or 5) or a perfect square greater than one (4 or 6). So, the successful outcomes are 1, 3, 4, 5, and 6. There are 5 successful outcomes in total.
Step 2: Determine the total number of possible outcomes.
Since we have a fair die, the total possible outcomes are 6.
Step 3: Calculate the probability.
Divide the number of successful outcomes by the total number of possible outcomes:
Probability = (Number of successful outcomes) / (Total number of possible outcomes)
Probability = 5/6
Therefore, the probability that an odd number or a perfect square greater than one shows up when rolling a fair die is 5/6.