A 2.00 kg box slides down a rough incline plane from a height h of 1.15 m. The box had a speed of 2.77 m/s at the top and a speed of 2.34 m/s at the bottom. Calculate the mechanical energy lost due to friction (as heat, etc.). (in J)
PE at top+KE at top-mechEnergyLost=KE at bottom.
mgh+1/2 m 2.77^2-MELost=1/2 m 2.34^2
solve for ME lost