A single fair die is tossed find the probability of rolling a number different than 12.
Please help me.
Find probability of rolling 12 which is 6 on both dice
1/6 * 1/6
It is (1 - that)
To find the probability of rolling a number different than 12 on a fair die, we first need to determine the total number of possible outcomes and the number of favorable outcomes.
The total number of outcomes when rolling a fair die is 6 because there are 6 sides, each labeled with a different number (1, 2, 3, 4, 5, and 6).
Since the die cannot show a number greater than 6, there are zero favorable outcomes for rolling a 12.
Therefore, the number of favorable outcomes is 6 - 0 = 6.
The probability is calculated by dividing the number of favorable outcomes by the total number of outcomes:
Probability = Number of Favorable Outcomes / Total Number of Outcomes
In this case, the probability would be:
Probability = 6 / 6 = 1
So, the probability of rolling a number different than 12 on a fair die is 1 or 100%.
Therefore, rolling a number different than 12 is guaranteed when rolling a single fair die.