a chemist has 800ml of 15% acidic solution.how much pure acid is to be added to make the solution 32% acidic
To solve this problem, we can use a basic formula that relates the amount of acid in a solution to its concentration:
Amount of Acid = Volume of Solution × Concentration of Acid
Let's break down the information given in the problem:
Initial solution:
Volume of initial solution = 800 mL
Concentration of initial solution = 15%
Final solution:
Concentration of acid in the final solution = 32%
Let's assume that x mL of pure acid needs to be added to the initial solution.
To find the amount of acid in the initial solution, we can use the formula:
Amount of Acid in initial solution = Volume of initial solution × Concentration of initial solution
Since the concentration is given as a percentage, we need to convert it to a decimal by dividing it by 100:
Amount of Acid in initial solution = 800 mL × (15/100) = 120 mL
Now, let's find the amount of acid in the final solution:
Amount of Acid in final solution = (Volume of initial solution + Volume of pure acid) × Concentration of acid in the final solution
We want the amount of acid in the final solution to be greater than or equal to 120 mL, so we can set up the equation:
Amount of Acid in final solution ≥ Amount of Acid in initial solution
(800 mL + x mL) × (32/100) ≥ 120 mL
Simplifying the equation, we get:
(8 + 0.32x) ≥ 1.20
Solving for x:
8 + 0.32x ≥ 1.20
0.32x ≥ 1.20 - 8
0.32x ≥ -6.80
Dividing both sides by 0.32, we get:
x ≥ -6.80/0.32
x ≥ -21.25 mL
Since we cannot add a negative amount of acid, we can conclude that we need to add 21.25 mL of pure acid to the initial solution in order to make the solution 32% acidic.
13600\31
amount of pure acid to be added --- x ml
.15(800) + x = .32(800+x)
solve for x