The acceleration of gravity is 10 m/s2.
What is the acceleration of a 46 kg pail of
cement that is pulled upward (not sideways)
with a force of 478 N?
Answer in units of m/s2.
To find the acceleration of the pail of cement, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
First, we need to calculate the net force acting on the pail of cement. Since the pail is being pulled upward, the net force is equal to the force applied minus the force of gravity pulling it downward.
The force of gravity can be calculated by multiplying the mass of the pail by the acceleration due to gravity. In this case, the mass of the pail is 46 kg and the acceleration due to gravity is given as 10 m/s^2.
Force of gravity = mass * acceleration due to gravity
Force of gravity = 46 kg * 10 m/s^2
Force of gravity = 460 N
Next, we can calculate the net force by subtracting the force of gravity from the applied force.
Net force = applied force - force of gravity
Net force = 478 N - 460 N
Net force = 18 N
Now, we can use Newton's second law to find the acceleration of the pail.
acceleration = net force / mass
acceleration = 18 N / 46 kg
acceleration = 0.39 m/s^2
Therefore, the acceleration of the 46 kg pail of cement being pulled upward with a force of 478 N is approximately 0.39 m/s^2.
M(g+a)= 478.
a = ?