How many grams of cesium chloride (CsCl) will be needed to make 750. mL of a 0.100 M
CsCl aqueous solution? The formula mass of CsCl is 168.36 g/mol.
Remember
Molarity: M = (mol solute) / (L of solution)
I need help solving this problem
mass=molarity*volumeinliters*molmass
= .1*.75*168 grams
To solve this problem, we can use the formula for molarity:
M = (mol solute) / (L of solution)
First, we need to calculate the number of moles of CsCl that we'll need for the solution.
Moles = Molarity × Volume
= 0.100 mol/L × 0.750 L
= 0.075 mol
Next, we need to find the mass of CsCl. We can use the formula mass (molar mass) to do this.
Mass = Moles × Formula Mass
= 0.075 mol × 168.36 g/mol
= 12.63 g
Therefore, you will need approximately 12.63 grams of cesium chloride (CsCl) to make 750 mL of a 0.100 M CsCl aqueous solution.