The Volume of air in a car tire is 800cm^3 and the pressure is 290kPa.

Determine the volume the air would occupy as soon as the tire bursts on a day when the atmospheric pressure is 204kPa.

(Assume that the temperature remains constant and assume an ideal gas)

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The Volume of air in a car tire is 800cm^3 and the pressure is 290kPa.

Determine the volume the air would occupy as soon as the tire bursts on a day when the atmospheric pressure is 102kPa.

(Assume that the temperature remains constant and assume an ideal gas)

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To determine the volume the air would occupy as soon as the tire bursts, we need to use Boyle's Law, which states that for an ideal gas at constant temperature, the pressure and volume are inversely proportional.

Boyle's Law equation is given as: P1 * V1 = P2 * V2

Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume

In this case:
P1 = 290 kPa (initial pressure)
V1 = 800 cm^3 (initial volume)
P2 = 204 kPa (final pressure)
V2 = unknown (final volume)

We can rearrange the equation to solve for V2:
V2 = (P1 * V1) / P2

Substituting the given values:
V2 = (290 kPa * 800 cm^3) / 204 kPa

Now, we need to convert the volume to the correct units before performing the calculation. Since the final volume is unknown, we can leave it in cubic centimeters (cm^3) for now.

Now, let's calculate the answer:

V2 = (290 kPa * 800 cm^3) / 204 kPa
V2 = 116000 cm^3 / 204 kPa

To simplify the units, we can convert kPa to cm^3 by recognizing that 1 kPa = 1000 cm^3:

V2 = (116000 cm^3) / (204 kPa * 1000 cm^3)
V2 = 116 / 204 cm^3

Therefore, the volume the air would occupy as soon as the tire bursts on a day when the atmospheric pressure is 204 kPa is approximately 0.569 cm^3.