Consider the functions defined by f(x)=6x-2, g(x)=-x^2-4x+1, find the following:
f(t)
g(a)
wherever you see an x , replace it with t for f(t)
f(t) = 6t - 2
do the same thing for your second question.
To find the value of f(t), we substitute t into the function f(x)=6x-2:
f(t) = 6t - 2
Similarly, to find the value of g(a), we substitute a into the function g(x)=-x^2-4x+1:
g(a) = -(a)^2 - 4(a) + 1
Now we have the following values:
f(t) = 6t - 2
g(a) = -(a)^2 - 4(a) + 1
To find f(t), you substitute t into the equation f(x) = 6x - 2 and replace x with t.
So, f(t) = 6t - 2.
To find g(a), you substitute a into the equation g(x) = -x^2 - 4x + 1 and replace x with a.
So, g(a) = -(a)^2 - 4(a) + 1.
Therefore, the values are:
f(t) = 6t - 2,
g(a) = -a^2 - 4a + 1.