Find the surface area of a right regular square pyramid with a side and a slant height of 9in. Help I know its tricky??

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To find the surface area of a right regular square pyramid, you need to calculate the area of the base and the area of the four triangular faces.

1. Start by finding the area of the base.
Since the pyramid is a right regular square pyramid, the base is a square.
Given the side length (S), you can find the area of the base (B) using the formula: B = S²

2. Next, calculate the area of one of the triangular faces.
To find this, you need to determine the length of one of the triangular sides using the Pythagorean theorem.
The slant height (L) and the height of the triangular face (H) form a right triangle. The height of the triangular face is equal to the height of the pyramid.
Use the formula: L² = S² + H², where H is the height of the triangular face.

Rearrange the formula to solve for H:
H² = L² - S²
H = √(L² - S²)

Now that you have the height of the triangular face, you can calculate the area of one triangular face (T):
T = (1/2) * S * H

3. Multiply the area of one triangular face by 4, since the pyramid has four of these faces.

4. Add the area of the base to the total area of the triangular faces to get the surface area of the pyramid:
Surface Area = B + (4 * T)

Now let's calculate the surface area of the pyramid with a side length (S) and a slant height (L) both equal to 9 inches.

To find the surface area of a right regular square pyramid, you need to calculate the area of the base and the lateral faces.

1. Calculate the area of the base:
Since the pyramid is a right regular square pyramid, the base is a square. Given that the length of a side of the square is 's,' the area of the base can be found by squaring the length of the side. In this case, the side length is not provided, so we are missing a crucial piece of information.

2. Find the height of the pyramid:
However, we are given the slant height of the pyramid, which is defined as the distance from the vertex (top) of the pyramid to a corner on the base. In this case, the slant height is 9 inches.

With this information, we need to use the Pythagorean theorem to find the height of the pyramid. In a right regular square pyramid, the height (h) is the perpendicular distance from the base to the vertex. By using the slant height (l) and the side length (s) of the base, the Pythagorean theorem can be applied as follows:

h^2 = l^2 - (s/2)^2

Substituting the given values:
h^2 = 9^2 - (s/2)^2

This equation will allow you to find the height of the pyramid, which is necessary for finding the surface area.

Once you have the height, 'h,' and the side length, 's,' you can calculate the area of the base by squaring the side length (s^2), and the lateral surface area by applying the formula:

Lateral Surface Area = 4 × (1/2) × s × l

where 's' is the side length of the base, and 'l' is the slant height.

Without the side length, it is not possible to provide an exact solution to find the surface area of the pyramid. However, by following the steps mentioned above, you should be able to calculate the missing side length and subsequently the surface area of the pyramid.

not tricky at all, if you take the time to draw a diagram.

Label the 4 base corners ABCD and the vertex P.

Drop an altitude to the center of the pryamid's base, point Q.

Draw a perpendicular line from Q to the center of one of the base sides. It meets at point R.

Then, triangle PQR is a right triangle, with legs 9 and 4.5, so its hypotenuse is s = 4.5√5, the slant height of the pyramid.

s is also the altitude of one of the pyramid's triangular faces. Now you have four triangles with base 9 and height s.

Calculate their areas, and add on the base of 9^2.