A particle moves in a circle of radius 2cm at a speed given bye V=4t where V is in cm/s and t is in second. Find the tengential acceleration at t=1 second.
If you are only looking at tangential acceleration (not centripetal) then only tangential velocity matters
v = 4 t cm/s * 1 m/100 cm
= .04 t m/s
tangential acceleration = dv/dt = .04 m/s^2
a partical moves on circular of radius 30cm its liner speed is given by v 2t find the radial and tangantial acclartion at t 3sec
To find the tangential acceleration at t = 1 second, we need to find the first derivative of the velocity function V(t) = 4t with respect to time. This will give us the expression for acceleration, as acceleration is the derivative of velocity with respect to time.
First, let's differentiate V(t) = 4t with respect to time:
dV/dt = 4
Since the derivative of V(t) = 4t is a constant value of 4, the tangential acceleration at any time t will also be a constant value of 4 cm/s².
So, the tangential acceleration at t = 1 second is simply 4 cm/s².