50 Ltr. Of a certain liquid is confined in a piston system at the extenal pressure 100 atm this pressure suddenly released and liquid is expanded against a contant atm pressure , vol. Of liquid increases by 1 Ltr and the final pressure of the liquid is 10 atm. Find the work done.

To find the work done during the expansion of the liquid, we can use the formula for work done by a gas:

Work = Pressure * Change in Volume

Given:
Initial volume of the liquid, V1 = 50 L
External pressure, P1 = 100 atm
Change in volume, ΔV = 1 L
Final pressure of the liquid, P2 = 10 atm

We need to calculate the work done during the expansion, so let's substitute the values into the formula:

Work = (P1 - P2) * ΔV

Work = (100 atm - 10 atm) * 1 L

Work = 90 atm * 1 L

Since atm is a unit of pressure, and work is typically expressed in units of energy, we need to convert atm to a unit of energy called joules (J).

To do this, we need to know the conversion factor between atm and J. The conversion factor is:

1 atm = 101.325 J

Multiplying the work by the conversion factor, we get:

Work = 90 atm * 1 L * 101.325 J/atm

Work = 9092.25 J

So, the work done during the expansion of the liquid is 9092.25 joules.

To find the work done in this scenario, we can use the formula:

Work = Pressure * Change in Volume

First, let's calculate the change in volume. We are given that the volume of the liquid increases by 1 liter.

Change in Volume = 1 L - 0 L (initial volume)

Now, we can calculate the work done:

Work = Pressure * Change in Volume

We have the initial pressure as 100 atm and the final pressure as 10 atm.

Work = (100 atm - 10 atm) * 1 L

Simplifying, we get:

Work = 90 atm * 1 L

Since we cannot multiply different units, we need to convert atm * L to a common unit. The unit for work is usually joules (J), so we can convert atm * L to joules.

1 atm = 101.325 J (approximately)
1 L = 0.001 m^3

Therefore,

Work = 90 atm * 1 L * 101.325 J/atm * 0.001 m^3/L

Work = 9,132.15 J

So, the work done in this scenario is approximately 9,132.15 joules.

4600J i.e 1lit.atm

Here p and v both are change
Delta(pv) apply here and get solution

1L.atm