how you would prepare 250 mL of 0.25 M NaOH from solid NaOH and water?
How many mols NaOH do you need? That's M x L = ? mols NaOH.
Then mols NaOH = grams NaOH/molar mass NaOH. You know mols and molar mass, solvle for grams NaOH.
I DONT KNOW PLEASE TELL
You need 3.66g of NaoH weighed into a 250mL flask and made up to mark
58*0.25*250/1000= 3.66g
To prepare 250 mL of a 0.25 M NaOH solution from solid NaOH and water, you will need to calculate the amount of solid NaOH required and then mix it with the appropriate volume of water. Here's how you can do it:
Step 1: Determine the amount of NaOH needed:
To calculate the amount of NaOH required, you will use the formula:
M1V1 = M2V2
Where:
M1 = Initial concentration (0.25 M)
V1 = Initial volume (unknown)
M2 = Final concentration (0.25 M)
V2 = Final volume (250 mL = 0.25 L)
Rearranging the formula, we get:
V1 = (M2 * V2) / M1
V1 = (0.25 M * 0.25 L) / 0.25 M
V1 = 0.25 L
This means you need 0.25 L (or 250 mL) of the 0.25 M NaOH solution.
Step 2: Dissolving the solid NaOH:
Since the density of a 0.25 M NaOH solution is approximately 1 g/mL, you will need 0.25 x 1 = 0.25 grams of NaOH.
Take the calculated amount of NaOH (0.25 grams) and add it to a container.
Step 3: Adding water:
Next, add distilled water to the container gradually while stirring until the final volume reaches 250 mL. Ensure that the NaOH dissolves completely in the water, creating a clear solution. Using a volumetric flask or graduated cylinder can make it easier to measure the volume accurately.
Step 4: Safety precautions:
Be cautious when handling NaOH, as it is a caustic substance. Wear protective goggles and gloves to avoid any contact with the skin or eyes. Also, make sure to work in a well-ventilated area.
Remember, it's always essential to double-check your calculations and ensure your measurements are accurate when preparing chemical solutions.