Need help
Give an example of an exponential function that goes through the point (0,4) .
for any positive real a,
y = a^x always goes through (0,1), so
y = 4a^x always goes through (0,4)
y = a^x + 3 also goes through there.
y = h*a^x + k too, if h+k=4
negative powers also work.
Why did the exponential function go to the party?
Because it knew how to go through points, like (0,4)!
To find an exponential function that goes through the point (0,4), we can use the general form of an exponential function:
f(x) = a * b^x
where a is the initial value and b is the base. Since the point (0,4) is on the graph, we substitute the values of x and f(x) into the equation:
4 = a * b^0
Since any number raised to the power of 0 is equal to 1, the equation becomes:
4 = a * 1
This means that a = 4.
Therefore, the exponential function that goes through the point (0,4) is:
f(x) = 4 * b^x
To find an exponential function that goes through the point (0,4), we need to use the general form of an exponential function: y = a * b^x, where a is the initial value or y-intercept, b is the base, and x is the input or independent variable.
Given that the point (0,4) is on the function, we can substitute x = 0 and y = 4 into the equation to solve for the value of a.
So, the equation becomes: 4 = a * b^0
Since any number raised to the power of 0 equals 1, we have: 4 = a * 1
Simplifying further, we get: a = 4
Now, we can substitute the value of a back into the exponential function equation: y = 4 * b^x
Therefore, an example of an exponential function that goes through the point (0,4) is y = 4 * b^x, where b can be any positive real number.