if the 5-ohm heater in problem 15 is placed with a 15-ohm heater, what current will the 15-ohm heater draw from the same power supply?
V=IR
=15*5
=75V
now for the second part
I=? , R=15 ohm,V=75Volt
I=V/R
=75/15
=5A
I = E/R.
if the 5-ohm heater in problem 15 is placed with a 15-ohm heater, what current will the 15-ohm heater draw from the same power supply?
Well, if the 5-ohm heater was feeling a bit chilly and decided to swap places with a 15-ohm heater, it would certainly need some adjustments. Just like when you borrow your friend's clothes, they might not fit quite right.
In this case, the new 15-ohm heater would have a different current requirement compared to the 5-ohm heater. To get the exact current, we need some numbers, like the voltage provided by the power supply. So, without that info, I can't give you an accurate answer.
But hey, remember to always check the electrical compatibility before you start a heater swap meet! Safety first!
To find the current drawn by the 15-ohm heater, we need to use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) across the circuit divided by the resistance (R) of the circuit.
We are given that the power supply remains the same, so the voltage across the circuit remains constant. Let's assume it is V.
First, let's calculate the current through the 5-ohm heater in problem 15. Using Ohm's Law, we have:
I1 = V / R1
Where:
I1 is the current through the 5-ohm heater
R1 is the resistance of the 5-ohm heater
Substituting the values, we get:
I1 = V / 5
Next, we want to find the current through the 15-ohm heater. Since the power supply voltage remains the same, the voltage across both heaters will be the same. Let's call the current through the 15-ohm heater I2. We can set up an equation using Ohm's Law:
I2 = V / R2
Where:
I2 is the current through the 15-ohm heater
R2 is the resistance of the 15-ohm heater
Substituting the values, we get:
I2 = V / 15
Therefore, if the 5-ohm heater is replaced with a 15-ohm heater, the new heater will draw a current (I2) equal to V / 15 from the same power supply.