Calculate the specific gravity of a liquid given the following information: m = 59.30 g, mA = 33.78 g, mL = 43.60 g.
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To calculate the specific gravity of a liquid, we need to first understand what specific gravity is. Specific gravity is the ratio of the density of a liquid to the density of a reference substance. The reference substance used most commonly is water at a specified temperature. In this case, we'll assume the reference substance is water at 4 degrees Celsius.
The density of an object is given by the formula:
Density = mass / volume
We are given the masses of the liquid (m) and the masses of the empty container (mA) and container with the liquid (mL).
To find the volume of the liquid, we need to subtract the mass of the empty container from the mass of the container with the liquid:
Volume of liquid = mL - mA
Now, let's substitute the values into the formula to calculate the density of the liquid:
Density of liquid = m / (mL - mA)
To calculate the specific gravity, we need to divide the density of the liquid by the density of water at 4 degrees Celsius. The density of water at 4 degrees Celsius is approximately 1 g/mL.
Specific gravity = (m / (mL - mA)) / density of water
Let's substitute the given values into the equation and calculate the specific gravity:
Specific gravity = (59.30 g / (43.60 g - 33.78 g)) / 1 g/mL
Specific gravity = 1.042
Therefore, the specific gravity of the liquid is approximately 1.042.