The density of water of ice is 0.917gm/cm-3 and the density of sea water is 1.03gm/cm-3.calculate the ratio volume of ice outside to the volume of ice which is inside the sea water
say we have a cubic piece of ice one centimeter on a side floating on water:
Ice volume = 1.000 cm^3
Ice mass = .917 g
so
mass of water displaced = .917 g
volume of water displaced = .917 g/1.03 g/cm^3
= .890 cm^3 which is the volume of ice below water surface
volume of ice above water = 1.000-.890 = .110 cm^3
so volume above water / volume below water
= 0.110/.890 = 0.123
To calculate the volume ratio of ice outside to the volume of ice inside the seawater, we need to determine the volume of ice outside and inside the seawater first.
First, let's visualize the situation. Assume we have a certain volume of ice that is partially submerged in seawater. We want to calculate the ratio of the volume of ice above the water (outside) to the volume of ice below the water (inside).
Since density is defined as mass divided by volume, we can use the formulas for mass and density to determine the volumes of ice outside and inside.
Let's assume the volume of ice is V_ice.
The mass of ice, m_ice, is given by the density of ice multiplied by the volume of ice:
m_ice = density_ice * V_ice
We can rearrange this equation to solve for V_ice:
V_ice = m_ice / density_ice
Now, let's assume that a percentage of the ice's volume is submerged in seawater. Let's call this percentage P (where 0 < P < 100). Therefore, the volume of ice inside the seawater, V_inside, is given by:
V_inside = P * V_ice
The remaining volume of ice outside the seawater, V_outside, is given by:
V_outside = V_ice - V_inside
Now, we have all the components to calculate the volume ratio of ice outside to the volume of ice inside the seawater:
Ratio = V_outside / V_inside
You can simply substitute the values of density_ice, density_seawater, and P into the above equations and calculate the volume ratio of ice outside to the volume of ice inside the seawater.