Rank the following in order of increasing bond polarity: H-F, H-Br, F-F, Na-Cl.

Question

Rank the following in order of increasing bond polarity: H-F, H-Br, F-F, Na-Cl.

Is it this....?

F-F, H-Br, H-F, Na-Cl

Answer 1

Oh, you've got my gears turning! Allow me to clown around with your question.

Let's rank these species in terms of increasing bond polarity:

F-F: Ah, good old elemental fluorine bonding with itself. This bond is nonpolar, just like my taste in clown shoes.

H-Br: A dash of hydrogen and bromine in the mix. This bond is moderately polar, resembling the delicate balance of a clown riding a unicycle on a tightrope.

H-F: Now we have hydrogen and good ol' fluorine teaming up. This bond is highly polar, like a clown in a tuxedo—noticeably fancy and electrifying.

Na-Cl: And for the grand finale, we have sodium and chlorine coming in hot. This bond is super-duper polar, stronger than a clown sneezing confetti out of their nose.

So, our final ranking is: F-F, H-Br, H-F, Na-Cl. Ta-da!

Answer 2

The correct ranking of the bonds in increasing bond polarity is as follows:

F-F, H-Br, H-F, Na-Cl

Answer 3

To rank the molecules in order of increasing bond polarity, we need to consider the electronegativity of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond.

In general, the greater the difference in electronegativity between two atoms, the more polar the bond between them will be.

First, let's determine the electronegativity values of the atoms involved:

Hydrogen (H): 2.2
Fluorine (F): 3.98
Bromine (Br): 2.96
Sodium (Na): 0.93
Chlorine (Cl): 3.16

Now, let's compare the pairs of atoms and determine their differences in electronegativity:

F-F: Electronegativity difference = 3.98 - 3.98 = 0 (nonpolar bond)
H-Br: Electronegativity difference = 2.96 - 2.2 = 0.76 (polar bond)
H-F: Electronegativity difference = 3.98 - 2.2 = 1.78 (polar bond)
Na-Cl: Electronegativity difference = 3.16 - 0.93 = 2.23 (polar bond)

Based on the electronegativity differences, we can conclude that the bonds in increasing order of polarity are:

F-F (nonpolar) < H-Br (polar) < H-F (polar) < Na-Cl (polar)

So, the correct order is:

F-F, H-Br, H-F, Na-Cl.

Rank the following in order of increasing bond polarity: H-F, H-Br, F-F, Na-Cl.

I agree

Oh, you've got my gears turning! Allow me to clown around with your question.

The correct ranking of the bonds in increasing bond polarity is as follows:

To rank the molecules in order of increasing bond polarity, we need to consider the electronegativity of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond.