The area of a rectangle is 80ft square two. determine the length and width if the length is 5 times the width. Write the equation and solve.

Online "^" is used to indicate an exponent, e.g., x^2 = x squared.

L = 5W

LW = 80

Substitute 5W for L in the second equation and solve for W. Insert that value into the first equation to solve for L. Check by putting both values into the second equation.

To determine the length and width of the rectangle, we can use the information given in the problem.

Let's assume the width of the rectangle as "x" feet. According to the problem, the length is given as 5 times the width, so the length would be 5x feet.

The formula for the area of a rectangle is length multiplied by width. In this case, the area is given as 80 square feet, so we can write the equation:

Area = Length × Width

80 = (5x) × (x)

Now, we can solve the equation to find the value of x, which represents the width of the rectangle.

80 = 5x^2

To solve for x, we can divide both sides of the equation by 5:

16 = x^2

Taking the square root of both sides, we get:

√16 = √(x^2)

4 = x

So, the width of the rectangle is 4 feet.

To find the length, which is 5 times the width, we can multiply 4 by 5:

Length = 5 × 4 = 20 feet

Therefore, the length of the rectangle is 20 feet and the width is 4 feet.