What is the total number of joules of hear needed to change 200g of ice to water at O degree Celcius?
Pjujt
To find the total number of joules of heat needed to change ice to water at 0 degrees Celsius, we can use the specific heat capacity of ice and water and the heat of fusion.
The specific heat capacity (c) of ice is 2.09 J/g°C, which means it takes 2.09 joules of heat to raise the temperature of 1 gram of ice by 1 degree Celsius.
The specific heat capacity (c) of water is 4.18 J/g°C, which means it takes 4.18 joules of heat to raise the temperature of 1 gram of water by 1 degree Celsius.
The heat of fusion (ΔHfus) of ice is 334 J/g, which means it takes 334 joules of heat to change 1 gram of ice at 0 degrees Celsius to water at 0 degrees Celsius.
To find the total number of joules of heat needed to change 200 grams of ice to water at 0 degrees Celsius, we can follow these steps:
1. Calculate the heat required to warm the ice from -10°C (the temperature at which most freezers operate) to 0°C:
Q1 = (mass of ice) x (specific heat capacity of ice) x (change in temperature)
= 200 g x 2.09 J/g°C x (0°C - (-10°C))
= 200 g x 2.09 J/g°C x 10°C
= 4180 J
2. Calculate the heat required to melt the ice at 0°C:
Q2 = (mass of ice) x (heat of fusion of ice)
= 200 g x 334 J/g
= 66800 J
3. Add the two results together to find the total heat required:
Total heat = Q1 + Q2
= 4180 J + 66800 J
= 70980 J
Therefore, the total number of joules of heat needed to change 200 grams of ice to water at 0 degrees Celsius is 70980 J.