what is diameter of the atomic nucleus of a lead atom is 1.75x10 negative15m
Tangina mo gusro ko formula hinde lang puro problemaaaaa 🔪🔪🔪🔫🔫
sounds like the response to a question on Jeopardy!
Want to revise the syntax?
Does anyone have an answer to this
To determine the diameter of the atomic nucleus of a lead atom, we need to use the given information:
Diameter = 1.75 x 10^(-15) m
The diameter of an object is the distance between two points on its outermost surface, passing through its center. In this case, the nucleus is assumed to be spherical, so we can calculate the diameter using the formula:
Diameter = 2 * Radius
To find the radius of the nucleus, we divide the diameter by 2:
Radius = Diameter / 2
Substituting the given value, we have:
Radius = (1.75 x 10^(-15) m) / 2
Now, let's calculate the radius:
Radius = 8.75 x 10^(-16) m
Therefore, the radius of the atomic nucleus of a lead atom is approximately 8.75 x 10^(-16) m.