A man buys 120 oranges at 6 a rupee and 12atmore at 5 a rupee and he sold the whole lot for 4 a rupee. What was his total profit and profit % ?

Ans- Rs16, 36 4/11%

Please help me to get the right solution of it.

Thnx

Dear your answer is wrong

To find the right solution, we need to calculate the total cost price and the total selling price.

Let's start with the cost price:

The man buys 120 oranges at 6 rupees each, so the cost of the first 120 oranges would be 120 x 6 = 720 rupees.

The man also buys 12 more oranges at 5 rupees each, so the cost of these additional oranges would be 12 x 5 = 60 rupees.

Therefore, the total cost price of all the oranges is 720 + 60 = 780 rupees.

Next, let's find the selling price:

The man sells the entire lot for 4 rupees per orange.

He bought a total of 120 + 12 = 132 oranges.

So, the total selling price of all the oranges is 132 x 4 = 528 rupees.

To find the profit, we need to subtract the cost price from the selling price:

Profit = Selling price - Cost price
Profit = 528 - 780 = -252

Since the profit is negative, it means the man incurred a loss of 252 rupees.

To calculate the profit percentage, we need to use the formula:

Profit Percentage = (Profit / Cost price) x 100

Profit Percentage = (-252 / 780) x 100
Profit Percentage = -32.3%

However, the answer you provided states that the total profit is 16 rupees. It seems there might be an error in the question or the answer given.

Please double-check the values and calculations to ensure accuracy.

cost: (120 * 1/6) + (120 * 1/5) = 44

sales: (120+120)/4 = 60

profit: 60-44=16
% profit = 60/44 = 15/11

15/11 - 1 = 4/11 = .3636 = 36 4/11 %

It makes it harder to arrive at the solution when you have typos in the problem...