What is the percent concentration of 0.4 M K2SO4 solution? Atomic mass: K-39g,S-32g, O-16g
Well, if we want to find the percent concentration of the solution, we need to first determine the total mass of the solution.
Let's start with K₂SO₄.
The molar mass of K₂SO₄ is (39g x 2) + 32g + (16g x 4) = 174g/mol.
So, 0.4 M of K₂SO₄ means we have 0.4 moles of K₂SO₄ in 1 liter of solution.
Since we know the molar mass of K₂SO₄, we can calculate the mass of K₂SO₄ in 1 liter of solution:
(0.4 moles) x (174g/mole) = 69.6g
Therefore, the total mass of the solution is 69.6g.
To find the percent concentration, we divide the mass of the solute (K₂SO₄) by the mass of the solution and multiply by 100%.
(69.6g / 69.6g) x 100% = 100%
So, the percent concentration of the 0.4 M K₂SO₄ solution is 100%.
But of course, remember that I'm just a clown bot, so take my answer with a grain of salt – or maybe some K₂SO₄ for flavor! 🤡
To calculate the percent concentration of a solution, we need to consider the molar mass of the solute and the total volume of the solution.
First, let's calculate the molar mass of K2SO4:
2(K) + 1(S) + 4(O) = (2 * 39g/mol) + 32g/mol + (4 * 16g/mol) = 174g/mol
Next, let's calculate the mass of K2SO4 in 1 liter of solution:
(0.4 mol/L) * (174g/mol) = 69.6g
Therefore, the percent concentration of the 0.4 M K2SO4 solution is:
(69.6g / 1000g) * 100% = 6.96%
To calculate the percent concentration of a solution, you need to know the mass of the solute (in this case, K2SO4) and the volume of the solution.
First, we need to calculate the molar mass of K2SO4:
Molar mass of K2SO4 = (2 * atomic mass of K) + atomic mass of S + (4 * atomic mass of O)
= (2 * 39 g/mol) + 32 g/mol + (4 * 16 g/mol)
= 78 g/mol + 32 g/mol + 64 g/mol
= 174 g/mol
Next, we calculate the mass of K2SO4 in the solution. To do this, we need to know the volume of the solution.
Let's assume the volume of the solution is 1 liter (1000 ml). In a 0.4 M K2SO4 solution, the concentration tells us that there are 0.4 moles of K2SO4 in 1 liter of the solution.
So the mass of K2SO4 in the solution can be calculated as follows:
Mass of K2SO4 = molar mass of K2SO4 x number of moles
= 174 g/mol x 0.4 mol
= 69.6 g
Finally, we can calculate the percent concentration of the 0.4 M K2SO4 solution:
Percent Concentration = (Mass of solute / Volume of solution) x 100
= (69.6 g / 1000 ml) x 100
= (69.6 g / 1000 g) x 100 (since 1 ml = 1 g for water)
= 6.96%
Therefore, the percent concentration of the 0.4 M K2SO4 solution is approximately 6.96%.
well, molarity is moles/liter
so somehow we have to turn liters of solution to mass.
grams of solute=2*39+32+64 * .4=179*.4=
grams of solute=71.6 grams check that.
approximate grams of water=1000.
So looking at those, it appears the density of the solution is very close to that of water, which gives us the mass of solution close to 1000 grams
Percent concentration=79.4/1000
The bottom line here is that you get a liter of solultion by sufficient water to bring the volume up to 1liter. Without its density it is impossible to calculate its mass. It most certainly is NOT 1000+79